chemistry thermodynamics questions and answers pdf
2000 AP CHEMISTRY FREE RESPONSE QUESTIONS. Enthalpy of combustion of octane, Heat transferred $=$ Heat capacity $\times \Delta T$, $=\left(8.93 \mathrm{kJ} K^{-1}\right) \times(6.73 \mathrm{K})=60.0989 \mathrm{kJ}$, Molar mass of octane $\left(C_{8} H_{18}\right)=(8 \times 12)+(18 \times 1)=114$, $\therefore$ Internal energy change $(\Delta E)$ during combustion of one mole of, octane $=\frac{60.0989}{1.250} \times 114=5481.02 k J \mathrm{mol}^{-1}$, $C_{8} H_{18}(l)+\frac{25}{2} O_{2}(g) \rightarrow 8 C O_{2}(g)+9 H_{2} O(l)$, $\Delta n_{g}=8-\frac{25}{2}=-\frac{9}{2}$, $\Rightarrow$ Enthalpy change, $\Delta H=\Delta E+\Delta n_{g} R T$, $=\left(5481.02 \times 10^{3}\right)+(-4.5 \times 8.314 \times 300.78)$, $=\left(5481.02 \times 10^{3}\right)-11253.08 \mathrm{J} \mathrm{mol}^{-1}$, $=5492273.082 \mathrm{Jmol}^{-1}=5492.27 \mathrm{kJ} \mathrm{mol}^{-1}$, Q. By plotting graph between molar heat capacity and atomic mass, the molar heat capacity of $F r$, (atomic mass $=223$ ) would be $33.5 \mathrm{J} \mathrm{mol}^{-1} \mathrm{K}^{-1}$, Q. (i) $\quad \Delta S_{\text {reaction}}^{\circ}=\Sigma S^{\circ}(\text { product })-\Sigma S^{\circ}(\text { reactants })$ (iv) $\quad N_{2}(g)(1 \mathrm{atm}) \rightarrow N_{2}(g)(0.5 \mathrm{atm})$ $\frac{3}{2} O_{2}(g) \rightarrow O_{3}(g)$ at $298 K$ Thermodynamics Multiple choice Questions and answers pdf,mcqs,objective type questions,lab viva manual technical basic interview questions download $\therefore$ The enthalpy of polymerization $\left(\Delta H_{\text {poly }}\right)$ must be negative. In this page you can learn various important multiple choice questions on thermodynamics,mcq on thermodynamics, thermodynamics objective questions answers,thermodynamics short questions etc. $C(g)+O_{2}(g) \rightarrow C O_{2}(g) ; \Delta_{r} H^{\circ}=-393 k J m o l^{-1}$ (i) $\left.\quad \mathrm{CH}_{3} \mathrm{OH}(l)+\frac{3}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)\right]$ (ii) $4 A l+3 O_{2} \rightarrow 2 A l_{2} O_{3} ; \Delta G^{\ominus}=+22500 \mathrm{kJ}$ $\Delta G^{\circ}=-2.303 R T \log K$ (iii) by 2 and add to eqn. combustion of $C$ to $C O_{2} .$ The net free energy change is calculated $\Delta H$ and $\Delta S$ for the reaction: Explanation are given for understanding. Formula sheet. Questions Answer PDF Download. A compendium of past examination questions set on Physical Chemistry on the JF Chemistry paper and problem sheets ... Thermodynamics, Equilibria and Electrochemistry ... there is insufficient data supplied to answer the question. The standard free energy of a reaction is found to be zero. The chemical energy can be transformed into other forms of energy, e.g. In the isothermal expansion the temperature remains constants. (i) Write the relationship between $\Delta H$ and $\Delta U$ for the process at constant pressure and temperature. SHOW SOLUTION (ii) $\quad A g N O_{3}(s) \rightarrow A g N O_{3}(a q)$, (iii) $\quad I_{2}(g) \rightarrow I_{2}(s)$. Enthalpy of solution of $N H_{4} N O_{3}=\frac{5.282}{20} \times 80$ $\Delta H=\Delta_{f} H^{o}\left(H_{3} O^{+}\right)+\Delta_{f} H^{o}\left(C l^{-}\right)$ Compute the molar heat capacity of these elements and identify any periodic trend. Why would you expect a decrease in entropy as a gas condenses into liquid ? Molar heat capacity of $K(s)=0.756 \times 39=29.5 \mathrm{J} \mathrm{mol}^{-1} \mathrm{K}^{-1}$ Is there any enthalpy change in a cyclic process ? $\Delta G=\Delta H-T \Delta S$ (iii) 1 mol of a liquid X. SHOW SOLUTION By plotting graph between molar heat capacity and atomic mass, the molar heat capacity of $F r$ $-(1) \quad \Delta S=-v e$ Question from very important topics are covered by NCERT Exemplar Class 11. Express the change in internal energy of a system when PV diagrams - … Also calculate enthalpy of solution of ammonium nitrate. Get Class 11 Chemistry Thermodynamics questions and answers to practice and learn the concepts. Thermodynamics article. Home » Chemistry » Thermodynamics » First Law of Thermodynamics » Give the comparison of work of expansion of an ideal Gas and a van der Waals Gas. Multiply eqn. Give suitable examples. The given equations are: $\Delta G_{f}^{\circ} C O_{2}(g)=-394.36 k J m o l^{-1}$ (ii) $\operatorname{CaCQ}(s)+2 H^{+}(a q) \rightarrow C a^{2+}(a q)+H_{2} O(l)+C O_{2}(g)$ (i) No heat is absorbed by the system from the surroundings, but work (w) is done on the system. A-Level Chemistry. Also, the order of entropy for the three phases of the matter is $S(g)>>S(l)>S(s)$ The standard Gibbs energy of reaction (at $1000 K)$ is $-8.1$ $k J m o l^{-1} .$ Calculate its equilibrium constant. Since Gibbs energy change is positive, therefore, at the reaction is not possible. [NCERT] SHOW SOLUTION Energy required for vapourising $2.38 g$ of $\mathrm{CO}$ You will get here all the important questions with answers for class 11 Chemistry Therodynamics and chapters. $\Delta T=286.4-296.5=-10.1 K$ since $\Delta_{r} G^{\circ}$ is negative, the reaction will be spontaneous. of water vaporised $=\frac{10}{18}=0.56$, $\therefore W=-p_{e x} \Delta V \quad\left(\Delta V=\frac{n R T}{P_{e x t}}\right)$, $=-p_{e x} \frac{n R T}{P_{e x t}}=-n R T$, $=-0.56 \times 8.314 \times 10^{-3} \times 373.15=-1.737 k J$, $\Delta U=\Delta H-P \Delta V=\Delta H-n R T$, Q. SHOW SOLUTION $\Delta_{r} H^{\circ}=-726 \mathrm{kJmol}^{-1}$ Molar mass of $C O=28 g \mathrm{mol}^{-1}$ $\Delta_{r} H^{\circ}=-726 k J m o l^{-1}$ $=\left(2 S_{F e_{2} O_{3}}^{\circ}\right)-\left(4 S_{F e(s)}^{\circ}+3 S_{O_{2}}^{\circ}(g)\right)$ $\Delta G=\Delta H-T \Delta S-v e=\Delta H-(+v e)(-v e)$. Standard enthalpy of vapourisation of benzene at its boiling point is $30.8 \mathrm{kJ} \mathrm{mol}^{-1} .$ For how long would a $100 \mathrm{Welectric}$ heater have to operate in order to vapourise $100 \mathrm{g}$ of benzene at its boiling point. Answer: -163 J / K SHOW SOLUTION $K_{p}$ for this conversion is $2.47 \times 10^{-29}$ What is the sign of $\Delta S$ for the forward direction? This will be so if $T<300.3 \mathrm{K}$, (ii) For reverse reaction to occur, should be tve for forward reaction. $\Delta H_{\text {Reaction}}=\Sigma \Delta H^{\circ}$ $f$ (Products) $-\Sigma \Delta H^{\circ}$ f $(\text {Reactants})$ (Given that power $=$ energy/time and $\left.1 W=1 J s^{-1}\right)$, Calculate the enthalpy change when $2.38 g$ of $C O$ vapourise at its boiling point. Give suitable examples. The temperature falls from $296.5 \mathrm{Kto} 286.4 \mathrm{K.Find}$ out the value of $q$ for calorimeter and its contents. All books are in clear copy here, and all files are secure so don't worry about it. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. Now $C_{v}=\frac{\Delta U}{\Delta T}$ and $\Delta T=1^{\circ} \mathrm{C}$ $\Delta_{r} H^{\circ}=-965 \mathrm{kJmol}^{-1}$ What is meant by average bond enthalpy ? In diatomic molecule bond enthalpy has fixed value, $e . You can access free study material for all three subject’s Physics, Chemistry and Mathematics. Open system : (i) Human being (ii) The earth (v) A satellite in orbit, Treat heat capacity of water as the heat capacity of calorimeter and its content). Q. $g$ of $C O_{2}$ from carbon and dioxygen gas. $\Delta n_{g}=8-\frac{25}{2}=-\frac{9}{2}$ Q. Q. $2 \Delta_{f} G^{\circ}\left(O_{2}\right)$ SHOW SOLUTION (iv) $\quad C(g)+2 H_{2}(g)+2 O_{2}(g) \longrightarrow C O_{2}(g)+2 H_{2}^{\circ} O$ If the system as a whole is at rest, so that the bulk mechanical energy due to translational or rotational motion is zero, then the $\Delta G=\Delta H-T \Delta S$ $\Rightarrow$ Enthalpy change, $\Delta H=\Delta E+\Delta n_{g} R T$ Heat released for the formation of $35.2 g$ of $C O_{2}$ Class XI Chapter 6 – Thermodynamics Chemistry Page 5 of 11 Answer From the expression of heat (q), q = m. c. ∆T Where, c = molar heat capacity m = mass of substance ∆T = change in temperature Substituting the values in the expression of q: q = 1066.7 J q = 1.07 kJ Question 6.10: منظمة التحرير الفلسطينية تأسيسها وتطورها pdf, Lippincott Pharmacology Pdf 2018 Free Download, تحميل كتاب الاكليل للهمداني الجزء الاول Pdf, Stem Application Form Of Alghurair Foundation, Practical Guide To Industrial Disputes Acts & Rules, Thermodynamics multiple choice questions and answers MCQ, ME6301 Engineering Thermodynamics Previous Year Question. (iii) w amount of work is done by the system and q amount of heat is supplied to the system. Based on Basic Engineering Thermodynamics by T.Roy Chowdhury, Tata McGrawHill Inc.,1988 - …. Give Its Limitations And Importance.? (iii) $\quad \Delta \mathrm{S}=-\mathrm{ve}$, (i) $\quad \mathrm{O}_{2}(g)+2 S O_{2}(g) \rightarrow 2 S O_{3}(g)$, (ii) $\quad \mathrm{CaC}_{2} \mathrm{O}_{4}(\mathrm{s}) \rightarrow \mathrm{CaCO}_{3}(\mathrm{s})+\mathrm{CO}(\mathrm{g})$, (iii) $2 \mathrm{H}_{2}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})$, (iii) $\quad \Delta \mathrm{S}=-\mathrm{ve}$, Q. \[ =\Delta_{d i s s} H^{o}=-75.2 k J m o l^{-1} \] change. $\Delta_{r} G^{\circ}=\Delta_{r} H^{\circ}-T \Delta_{r} S^{\circ}=0$ We know $=\frac{-\left(-8100 m o l^{-1}\right)}{2.303 \times 8.314 J K^{-1} m o l^{-1} \times 1000 K}=0.4230$ (ii) Under what conditions will the reaction occur spontaneously? $\Delta G_{f}^{o} \mathrm{CO}_{2}(g)=-394.36 \mathrm{kJ} \mathrm{mol}^{-1}$ Calculate the value of standard Gibb’s energy change at 298 K and predict whether the reaction is spontaneous or not. $-C l$ bond in $C C l_{4}(g)$ $\mathrm{CH}_{4}(\mathrm{g})+2 \mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{CO}_{2}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(l) \cdot\left(\Delta \mathrm{U}=-85389 \mathrm{Jmol}^{-1}\right)$ Register online for Chemistry tuition on Vedantu.com to score more marks in your examination. $C_{p}=\left(1.0 \mathrm{cal} K^{-1} g^{-1}\right)\left(18.0 \mathrm{g} \mathrm{mol}^{-1}\right)=18.0 \mathrm{cal} \mathrm{K}^{-1} \mathrm{mol}^{-1}$ Click Here for Detailed Notes of any chapter. Calculate the number of $k J$ necessary to raise the temperature of $60.0 \mathrm{g}$ of aluminium from $35-55^{\circ} \mathrm{C} .$ Molarheat capacity of $A l$ is $24 J m o l^{-1} K^{-1}$ $\Delta S_{\text {Reaction }}=\Sigma S_{m(\text { products })}^{\circ}-\Sigma S_{m(\text { reactants })}^{\circ}$ In what way internal energy is different from enthalpy ? Q. the condensation of diethyl ether is the reverse process, therefore, $\Delta S_{\text {condensation }}=-84.4 \mathrm{JK}^{-1} \mathrm{mol}^{-1}$, Q. SHOW SOLUTION Enthalpy change is measured at constant pressure SHOW SOLUTION SHOW SOLUTION $\Delta H-92.38 k J=-92380 J, R=8.314 J K^{-1} \mathrm{mol}^{-1}$ As per the second law of thermodynamics god exist, some person have believe that the world is so beautiful and only god can construct such beautiful world.Some scientist believe that the DNA structure is very much complicated and only god can create it.But as per the one scientist that god exist out of the our knowledge boundary. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. $ \therefore $ the enthalpy of polymerization $ \left ( \Delta H ) $ \quad \Delta S=+v e because! During polymerization is negative various molecules ( polyatomic ) not at what temperature, predict sign! Gibb ’ S Physics, Chemistry and Mathematics, C 2H5OH, is °C! Be a closed system this temperature and below this temperature and why are. 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Boiling point Problems Class 11 Chemistry thermodynamics questions and answers to practice and learn the concepts system H=U+P! The process at constant pressure and temperature sum of the following are open close or nearly isolated system process the...
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